# Physics 203 at Portland State 2014

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rainbow_project [2014/06/02 06:34]
delakins [Data]
rainbow_project [2014/06/03 19:18] (current)
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* $P_\text{sc}$ $\,​=\,​I_\text{sc}\!\cdot\!{\text{Area}}_\text{sc}$ $\,​\approx\,​I_\text{sc}\!\cdot\!2\pi\,​(D\sin\gamma)\,​D\Delta \gamma\;$, where $\,D$ is the distance from the droplet to the observer.         * $P_\text{sc}$ $\,​=\,​I_\text{sc}\!\cdot\!{\text{Area}}_\text{sc}$ $\,​\approx\,​I_\text{sc}\!\cdot\!2\pi\,​(D\sin\gamma)\,​D\Delta \gamma\;$, where $\,D$ is the distance from the droplet to the observer.
* $P_\text{sc}$ $=s\!\cdot\!P_\text{inp}$         * $P_\text{sc}$ $=s\!\cdot\!P_\text{inp}$
-        * $I_\text{sc}$ $=s\!\cdot\!I_\text{inp}\frac{d}{D^2\sin\gamma}\frac{\Delta d}{\Delta\gamma}$ $=s \cdot I_\text{inp}\frac{R^2\delta}{D^2\sin\gamma}\frac{\Delta \delta}{\Delta\gamma}$ $\sim I_\text{inp}\frac{\delta}{\sin\gamma}\frac{\Delta \delta}{\Delta\gamma}\;​$:​ here the factors //s//, //R//, and //D// are pretty constant (or too complicated to calculate) and do not contribute to the relative intensity at various angles and wavelengths+        * $I_\text{sc}$ $=s\!\cdot\!I_\text{inp}\frac{d}{D^2\sin\gamma}\left|\frac{\Delta d}{\Delta\gamma}\right|$ $=s \cdot I_\text{inp}\frac{R^2\delta}{D^2\sin\gamma}\left|\frac{\Delta \delta}{\Delta\gamma}\right|$ $\sim I_\text{inp}\frac{\delta}{\sin\gamma}\left|\frac{\Delta \delta}{\Delta\gamma}\right|\;$: here the factors //s//, //R//, and //D// are pretty constant (or too complicated to calculate) and do not contribute to the relative intensity at various angles and wavelengths

- **Index of refraction for water** ​ = 1.33.  This is the average value. We need its dependence on the wavelength $\lambda$!   - **Index of refraction for water** ​ = 1.33.  This is the average value. We need its dependence on the wavelength $\lambda$!
-  - **Average ​Solar Intensity on Earth** = 1367 $\frac{W}{m^2}$+  - **Average ​[[wp>​Sunlight]] ​Intensity on Earth** = 1367 $\frac{W}{m^2}$ ​