# Physics 203 at Portland State 2014

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final_exam_review
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final_exam_review [2014/06/10 19:19]
wikimanager [Review question 7]
final_exam_review [2014/06/10 19:28] (current)
wikimanager [Review question 6]
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* [....] E) 1.5 m   * [....] E) 1.5 m

-<color green>​Use the Single-Slit Dark Fringe Diffraction ​equation: ​Wsin(theta)=m(lambdato find angle at which light bends. ​Θ=arcsin(mλ/W). Then plug in Θ into the linear distance equation ​(L=tanΘ*Y) to solve for the screen to slit distance, L. </​color>​+  - <color green>​Use the single-slit diffraction ​equation ​for dark fringes</​color>​
+    * <color green>​$W\sin(\theta)=m\lambdato find the angle at which the light bends. ​</​color>​ + * <color green>​Second dark fringe means$m=2$. </​color>​ + * <color green>​Therefore$\theta=\arcsin\big(\!\frac{2\lambda}{W}\!\big)$</​color>​ + - <color green>Then plug in$\theta$​into the linear distance equation ​</​color>​ + * <color green>$y=L\tan\theta\;​$, ​to solve for the screen to slit distance, ​//L//</​color>​ + - <color green>​The final formula is </​color>​ + * <color green>​$L=\frac{y}{\tan\left[\arcsin\big(\!\frac{2\lambda}{W}\!\big)\right]}\$</​color>​

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